Kerala Plus One Physics Chapter Wise Previous Questions Chapter 8 Gravitation Question 1. The radius of the earth is: 8. 4. The satellite has a cylindrical shape 2 m in diameter by 4 m long and has a mass of 1,000 kg. (a) What is the value of K.E. Calculate the velocity of the satellite at both perigee and apogee. What is the radius of the orbit? Find (a) its speed in the orbit. How much is the gravitational force that keeps an artificial satellite of mass 3500 kg in orbit around the earth at an altitude of 4200 km - 11424671 An artificial satellite of mass 100 kg is in circular orbit at 500 km above the surface of earth What is the centripetal acceleration of the satellite (mass of earth is 6*1024 kg,radius of earth is 6400 km) - Physics - ii) g is independent of […] A satellite of mass 5500 kg orbits the Earth (mass = 6.0 x 10^24 kg) and has a period of 6200 s. Find (a) the magnitude of the Earth’s gravitational force on the satellite, (b) the altitude of the satellite. An artificial satellite of mass 200 kg revolves around the earth in an orbit of average radius 6670 km. How can you separate ammonion chloride and salt and explain Two plane mirrors are placed such that they make an angle between them. Determine the orbital period of the satellite. If the number of images formed by this system of mirrors is 9, find the angle … between the mirrors. The Envisat satellite is a large, inactive satellite with a mass of 8,211 kg (18,102 lb) that drifts at 785 km (488 mi), an altitude where the debris environment is the greatest—two catalogued objects can be expected to pass within about 200 m (660 ft) of Envisat every year —and likely to increase. Find the orbital speed. What is the binding energy of an artificial satellite of mass 1000 kg orbiting a) at a height of 500 km above the surface of the earth and b) close to the earth’s surface? The radius of Earth is approximately 6400 km. _____ predicted about artificial satellites about 300 years ago. 2. A satellite is in a circular orbit around an unknown planet. A communications satellite with a mass of 450 kg is in a circular orbit about the Earth. An artificial satellite circles the Earth in a circular orbit at a location where the acceleration due to gravity is 8.26 m/s2. Calculate the perturbations due to atmospheric drag and estimate the satellite's lifetime. According to NASA, “in terms of mass, a nanosat or nanosatellite is anything that weighs between 1 and 10 kilograms”. An artificial satellite revolves around the earth at a height of 1000 km. (a) Find the altitude of the satellite. Where M is the mass of the earth, R is the radius of the earth, h is the height from the surface of the earth where is an object is kept. PROBLEM 1.4 An artificial earth satellite is in an elliptical orbit which brings it to an altitude of 250 km at perigee and out to an altitude of 500 km at apogee. (b) its kinetic energy, (c) the potential energy of the earth satellite system and (d) its time period. 43. Shashankn8055 Shashankn8055 Answer: … Most of the artificial objects in outer space are in LEO.. The space directly above our atmosphere is filled with artificial satellites in orbit. What is the mass of the planet 44,795 results, page 2 Physics. Mass of the space ship = 1000 kg; mass of the sun = 2 × 10 30 kg; mass of mars = 6.4 × 10 23 kg; radius of mars = 3395 km; radius of the orbit of mars = 2.28 × 10 8 km; G = 6.6 7 × 10-11 N m 2 kg-2. Weight of a body depends directly on ‘g’. A satellite moves in a circular orbit of radius 35.793 km. Circular Orbits. i) g increases/decreases with the increasing altitude. 44. How to solve: A 1,000 kg satellite orbits the Earth with a speed of 5,997 m/s. Total energy in the orbital is given by E = − G M m 2 r = − 6.67 × 10 − 11 × 6 × 10 24 × 10 3 2 × 6.67 × 10 6 = 3 × 10 10 J [G = 6.67 x 10-11 S.I. Mass of earth = M = 6 x 10 24 kg; radius of earth = R = 6400 km = 6.4 x 10 6 m, G = 6.67 x 10-11 Nm 2 /kg 2. Orbital velocity of satellite doesn't depend on the mass of satellite. Find the total energy and binding energy of an artificial satellite of mass 1000 kg orbiting at height of 1600 km above the earths surface, [Given : G = 6.67 x 10⁻¹¹ Nm² / kg², R = 6400 km, M = 6400 km, M = 6 x 10²⁴ kg] (Ans : T.E.= - 2.501 x 10¹⁰J, B.E = 2.501 x 10¹⁰J) An artificial satellite circling the Earth completes each orbit in 139 minutes. 1 See answer pinao1978 is waiting for your help. A satellite of mass 1000 kg is supposed to orbit the earth at a height of 2000 km above the earth's surface. (b) Now the satelite is again given some kinetic energy and it is shifted into an orbit of radius 4R. The Earth's radius and mass are Re = 6.37e6 m, and Me = 5.97e24 kg. 1. If the distance between two masses is half then the force of gravitation becomes: 6. Brainly User Brainly User Given , ... density of water = 1000 kg/m", g = 9.8 m/s". 0.2. Mass of the earth =6×1024 kg=6×1024 kgg=6.67×10−11nm3kg−2g=6.67×10−11nm3kg−2. The value of ‘g’ depends on many factors like shape of earth, rotation of earth etc. An artificial satellite circling the Earth completes each orbit in 139 minutes. (a) Find the altitude of the satellite. An artificial satellite of mass 100 kg is in circular orbit of 500 km above the earth's surface.Take radius of earth as 6.5×10^6m.Find acceleration due to - 7929731 (The radius of the Earth is 6.38 106 m. The mass of the Earth is 5.98 1024 kg.) units, Radius of earth : R = 6400 km, Mass of earth : M = 6 x 10 24 kg] Find the total energy and binding energy of an artificial satellite of mass 800 kg orbiting at a height of 1800 km above the surface of the earth. A 1000-kg satellite travels with an orbital speed of 500 m/s around a planet at an orbital raduis of 8000 km. The gravitational force between the two masses is: F = G mM r2 = 6:67 10 11 2:10 21 10 3 (3:90 10 2)2 = 1:93 10 3 N 2. Here, m = 1000 kg r = 6.67 × 10 6 m M = 6 × 10 24 kg i. Orbital speed is given by v = G M r = 6.67 × 10 − 11 × 6 × 10 24 6.67 × 10 6 ≈ 7746 ms − 1 ii . A small satellite, miniaturized satellite, or smallsat is a satellite of low mass and size, usually under 500 kg (1,100 lb). A satellite with a mass of 1000 kg has a weight force of 9800 N at the Earth’s surface. They can be small enough to fit in the palm of your hand or as huge as the ISS. science. Get an answer for 'A satellite of mass 2500 kg is orbiting the Earth i n an elliptical orbit. A low Earth orbit (LEO) is an Earth-centred orbit with an altitude of 2,000 km (1,200 mi) or less (approximately one-third of the radius of Earth), or with at least 11.25 periods per day (an orbital period of 128 minutes or less) and an eccentricity less than 0.25. (The radius of the Earth is 6.38 106 m. The mass of the Earth is 5.98 1024 kg.) While all such satellites can be referred to as "small", different classifications are used to categorize them based on mass.Satellites can be built small to reduce the large economic cost of launch vehicles and the costs associated with construction. Unit of gravitational field strength is: 3. An artificial satellite of mass m is given some kinetic at the surface of the Earth so that it is positioned into an orbit of radius 2R (R = radius of Earth, M = mass of Earth) ? An artificial satellite has a mass of 600 kg and moving towards the moon. (MARCH-2010) a) Choose the correct alternative. The radius of the earth is 6.38×103km6.38×103km. geometry. given to satellite at the surface of Earth. A satellite of mass 1000 kg is supposed to orbit the earth at a height of 2000 km above the earth's surface. We examine the simplest of these orbits, the circular orbit, to understand the relationship between the speed and period of planets and satellites in relation to their positions and the bodies that they orbit. In System International, the value of G is 7. Physics. If the distance of the planet jupiterfrom the … Add your answer and earn points. tational constant G uses lead spheres with masses of 2.10 kg and 21.0 g whose centers are separated by about 3.90 cm. Artificial satellites vary in size and cost depending on the use they are put to. The distance of the moon from Earth is? Calculate its orbital K.E., the gravitational potential energy and the total energy = 6.0 x 10 24 kg and G = 6.67 x 10-11 N m 2 kg-2. Find a. its speed in the orbit b. its kinetic energy. The Soviet Union launched it into an elliptical low Earth orbit on 4 October 1957. An artificial satellite of mass 1000 kg revolves around the earth in circular orbit of radius 6500Km Calculate (a) Orbital velocity (b) Orbital Kinetic energy (c) Gravitational potential energy (d) Total energy in the orbit Experts plz help NO LINKS PLZZ - Physics - Gravitation So, the kinetic energy of the satellite (mass m) in a circular orbit with speed v can be written as. Physics. A satellite in Earth orbit has a mass of 100 $\mathrm{kg}$ and is at an alti… 03:40 A 500 -kg satellite is in a circular orbit at an altitude of $500 \mathrm{km… The speed of GPS satellite is: 5. Calculate the gravitational force between these spheres, treating each as a particle located at the center of the sphere. For the satellite, calculate the work done to put the satellite in orbit (mass of satellite is 1000 kg). An artificial satellite of mass 1000kg revolves around the earth in circular orbit of radius 6500 km Calculate (i) orbital velocity (ii) orbital kinetic energy - Physics - (II) Estimate the acceleration due to gravity at the surface of Europa (one of the moons of Jupiter) given that its mass is 4.9 $\times$ 10$^{22}$ kg and making the assumption that its mass per unit volume is the same as Earth's. AS satellite of mass 1000 kg is supposed to orbit the earth at a height of 2000 km above the earth's surface. Sputnik 1 (/ ˈ s p ʌ t n ɪ k, ˈ s p ʊ t n ɪ k /; "Satellite-1", or "PS-1", Простейший Спутник-1 or Prosteyshiy Sputnik-1, "Elementary Satellite 1") was the first artificial Earth satellite. The satellite is traveling with its long axis perpendicular to the velocity vector and it's drag coefficient is 2.67. A satellite in a nearly circular orbit is 2000 km above Earth's surface. The radius of the Earth is about 6366 km, so at 6366 km above the Earth’s surface, the distance from the centre of the Earth will have doubled.